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European Journal of Applied Sciences – Vol. 12, No. 4
Publication Date: August 25, 2024
DOI:10.14738/aivp.124.17327
Dialynas, T. E. (2024). Modified: Hubble’s Law. European Journal of Applied Sciences, Vol - 12(4). 431-436.
Services for Science and Education – United Kingdom
Modified: Hubble’s Law
Thanassis E. Dialynas
Department of Physics, University ofCrete,Heraklion, Crete, Greece
ABSTRACT
Based on natural grounds, we propose a (special - relativistic) “modification” of
Hubble’s Law [6, 7, 8, 9]. The advantage is that no galaxy can exceed the speed of
light, no matter how far it is. The disadvantage is that the equations appearing are
more difficult to handle and they are also non – invertible. The main tendencies of
the “theory” [8] remain the same.
Keywords: Hubble’s Law, "Modified" Hubble’s Law, Hubble’s constant, velocity of light,
“Maisie’s” galaxy.
INTRODUCTION
By Hubble’s Law [6, 7, 8], v = H * d and the necessary condition v < c, for H = 80 km/sec/Mpc,
a maximum radins of dmax = 12,2 Gly is expected. [ For H = 73,1 Km/sec/Mpc (dominant
value), dmax = 13,3 Gly].
The above “observation “[8] is purely phenomenological and does not come from a dynamical
theory (for instance General Relativity). Therefore, one can ask if finally, we have d > dmax (v
>c) from a dynamical theory what happens, i.e. can there be a velocity larger than light.
The usual answer given to this question is that the “observation” of velocities higher than c,
can happen and is due to the expansion of the space – time itself and not to the massive
objects themselves.
However, the light observed by spectroscopy comes from massive objects (galaxies) and their
velocity (if d >dmax exists) cannot exceed this of light.
We hope that the resolution of the “paradox” is given by the few next lines:
MAIN THEME
A) By Hubble’s law the velocity of a far galaxy is v = H * d where H is the Hubble constant
(dominant value):
H = 73,1 Km/sec/Mpc ≅ 2,37 * 10−18 sec−1
(1)
and d the distance of the far galaxy in appropriate units.
Therefore, if the mass of the galaxy is mG and is considered as one “compact” object its
(radial) momentum is
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Services for Science and Education – United Kingdom 432
European Journal of Applied Sciences (EJAS) Vol. 12, Issue 4, August-2024
PG = mG * H * d = mG * v (2)
However, the momentum of a mass (mG) in special relativity is
PG = mG * γ(v) v (3)
where γ = [1 − (
v
c
)
2
]
−
1
2 .
Subsequently equating expressions (3) and (2) we can have a transition from “Classical
Mechanics” to Special Relativity by demanding:
γ(v) v = H * d (4)
and of course, v = d = d
dt
(d).
Making the substitutions β = v
c
and χ = Hd
c
where
γ(β) * β = χ (5)
where γ(β) = = (1 − β
2
)
−
1
2.
Solving (5) for β we get
β = χ
√1+ χ2
< 1 (6)
for every χ greater than zero. (χ > 0)
Introducing the “dimensionless time” τ = H * t we have finally the o.d.e.
χ ’ = χ
√1+ χ2
(7)
with the initial condition χ (0) = χ0 – in general where χ0 ≥ 0. [Please note τ is the
“dimensionless time” t and χ the “dimensionless distance” d, of course χ’ = dx/dτ].
Equation (7) can be solved by the separation of variables (one indefinite integral) and after
four changes of variables one gets:
τ = f(χ) – f (χ0) (8)
where τ = H * t and χ = H∗d
c
and
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Dialynas, T. E. (2024). Modified: Hubble’s Law. European Journal of Applied Sciences, Vol - 12(4). 431-436.
URL: http://dx.doi.org/10.14738/aivp.124.17327
f(χ) = √1 + χ
2 +
1
2
ln |
√1+ χ2−1
√1+ χ2+1
| (9)
χ ∊ (0, +∞)
B) Let’s see some graphs:
(Fig I) [Ref 8]
(Fig II)
(Fig III) [Ref 8]